3.531 \(\int \frac {(a+b x^3)^{2/3}}{x} \, dx\)

Optimal. Leaf size=98 \[ \frac {1}{2} a^{2/3} \log \left (\sqrt [3]{a}-\sqrt [3]{a+b x^3}\right )+\frac {a^{2/3} \tan ^{-1}\left (\frac {2 \sqrt [3]{a+b x^3}+\sqrt [3]{a}}{\sqrt {3} \sqrt [3]{a}}\right )}{\sqrt {3}}-\frac {1}{2} a^{2/3} \log (x)+\frac {1}{2} \left (a+b x^3\right )^{2/3} \]

[Out]

1/2*(b*x^3+a)^(2/3)-1/2*a^(2/3)*ln(x)+1/2*a^(2/3)*ln(a^(1/3)-(b*x^3+a)^(1/3))+1/3*a^(2/3)*arctan(1/3*(a^(1/3)+
2*(b*x^3+a)^(1/3))/a^(1/3)*3^(1/2))*3^(1/2)

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Rubi [A]  time = 0.07, antiderivative size = 98, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.400, Rules used = {266, 50, 55, 617, 204, 31} \[ \frac {1}{2} a^{2/3} \log \left (\sqrt [3]{a}-\sqrt [3]{a+b x^3}\right )+\frac {a^{2/3} \tan ^{-1}\left (\frac {2 \sqrt [3]{a+b x^3}+\sqrt [3]{a}}{\sqrt {3} \sqrt [3]{a}}\right )}{\sqrt {3}}-\frac {1}{2} a^{2/3} \log (x)+\frac {1}{2} \left (a+b x^3\right )^{2/3} \]

Antiderivative was successfully verified.

[In]

Int[(a + b*x^3)^(2/3)/x,x]

[Out]

(a + b*x^3)^(2/3)/2 + (a^(2/3)*ArcTan[(a^(1/3) + 2*(a + b*x^3)^(1/3))/(Sqrt[3]*a^(1/3))])/Sqrt[3] - (a^(2/3)*L
og[x])/2 + (a^(2/3)*Log[a^(1/3) - (a + b*x^3)^(1/3)])/2

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rule 50

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + n + 1)), x] + Dist[(n*(b*c - a*d))/(b*(m + n + 1)), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 55

Int[1/(((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(1/3)), x_Symbol] :> With[{q = Rt[(b*c - a*d)/b, 3]}, -Simp[L
og[RemoveContent[a + b*x, x]]/(2*b*q), x] + (Dist[3/(2*b), Subst[Int[1/(q^2 + q*x + x^2), x], x, (c + d*x)^(1/
3)], x] - Dist[3/(2*b*q), Subst[Int[1/(q - x), x], x, (c + d*x)^(1/3)], x])] /; FreeQ[{a, b, c, d}, x] && PosQ
[(b*c - a*d)/b]

Rule 204

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTan[(Rt[-b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[-b, 2]), x] /
; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 266

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a
+ b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]

Rule 617

Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*Simplify[(a*c)/b^2]}, Dist[-2/b, Sub
st[Int[1/(q - x^2), x], x, 1 + (2*c*x)/b], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /;
FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rubi steps

\begin {align*} \int \frac {\left (a+b x^3\right )^{2/3}}{x} \, dx &=\frac {1}{3} \operatorname {Subst}\left (\int \frac {(a+b x)^{2/3}}{x} \, dx,x,x^3\right )\\ &=\frac {1}{2} \left (a+b x^3\right )^{2/3}+\frac {1}{3} a \operatorname {Subst}\left (\int \frac {1}{x \sqrt [3]{a+b x}} \, dx,x,x^3\right )\\ &=\frac {1}{2} \left (a+b x^3\right )^{2/3}-\frac {1}{2} a^{2/3} \log (x)-\frac {1}{2} a^{2/3} \operatorname {Subst}\left (\int \frac {1}{\sqrt [3]{a}-x} \, dx,x,\sqrt [3]{a+b x^3}\right )+\frac {1}{2} a \operatorname {Subst}\left (\int \frac {1}{a^{2/3}+\sqrt [3]{a} x+x^2} \, dx,x,\sqrt [3]{a+b x^3}\right )\\ &=\frac {1}{2} \left (a+b x^3\right )^{2/3}-\frac {1}{2} a^{2/3} \log (x)+\frac {1}{2} a^{2/3} \log \left (\sqrt [3]{a}-\sqrt [3]{a+b x^3}\right )-a^{2/3} \operatorname {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,1+\frac {2 \sqrt [3]{a+b x^3}}{\sqrt [3]{a}}\right )\\ &=\frac {1}{2} \left (a+b x^3\right )^{2/3}+\frac {a^{2/3} \tan ^{-1}\left (\frac {1+\frac {2 \sqrt [3]{a+b x^3}}{\sqrt [3]{a}}}{\sqrt {3}}\right )}{\sqrt {3}}-\frac {1}{2} a^{2/3} \log (x)+\frac {1}{2} a^{2/3} \log \left (\sqrt [3]{a}-\sqrt [3]{a+b x^3}\right )\\ \end {align*}

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Mathematica [A]  time = 0.08, size = 90, normalized size = 0.92 \[ \frac {1}{2} \left (a^{2/3} \log \left (\sqrt [3]{a}-\sqrt [3]{a+b x^3}\right )-a^{2/3} \log (x)+\left (a+b x^3\right )^{2/3}\right )+\frac {a^{2/3} \tan ^{-1}\left (\frac {\frac {2 \sqrt [3]{a+b x^3}}{\sqrt [3]{a}}+1}{\sqrt {3}}\right )}{\sqrt {3}} \]

Antiderivative was successfully verified.

[In]

Integrate[(a + b*x^3)^(2/3)/x,x]

[Out]

(a^(2/3)*ArcTan[(1 + (2*(a + b*x^3)^(1/3))/a^(1/3))/Sqrt[3]])/Sqrt[3] + ((a + b*x^3)^(2/3) - a^(2/3)*Log[x] +
a^(2/3)*Log[a^(1/3) - (a + b*x^3)^(1/3)])/2

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fricas [A]  time = 0.78, size = 122, normalized size = 1.24 \[ \frac {1}{3} \, \sqrt {3} {\left (a^{2}\right )}^{\frac {1}{3}} \arctan \left (\frac {\sqrt {3} a + 2 \, \sqrt {3} {\left (b x^{3} + a\right )}^{\frac {1}{3}} {\left (a^{2}\right )}^{\frac {1}{3}}}{3 \, a}\right ) - \frac {1}{6} \, {\left (a^{2}\right )}^{\frac {1}{3}} \log \left ({\left (b x^{3} + a\right )}^{\frac {2}{3}} a + {\left (a^{2}\right )}^{\frac {1}{3}} a + {\left (b x^{3} + a\right )}^{\frac {1}{3}} {\left (a^{2}\right )}^{\frac {2}{3}}\right ) + \frac {1}{3} \, {\left (a^{2}\right )}^{\frac {1}{3}} \log \left ({\left (b x^{3} + a\right )}^{\frac {1}{3}} a - {\left (a^{2}\right )}^{\frac {2}{3}}\right ) + \frac {1}{2} \, {\left (b x^{3} + a\right )}^{\frac {2}{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^3+a)^(2/3)/x,x, algorithm="fricas")

[Out]

1/3*sqrt(3)*(a^2)^(1/3)*arctan(1/3*(sqrt(3)*a + 2*sqrt(3)*(b*x^3 + a)^(1/3)*(a^2)^(1/3))/a) - 1/6*(a^2)^(1/3)*
log((b*x^3 + a)^(2/3)*a + (a^2)^(1/3)*a + (b*x^3 + a)^(1/3)*(a^2)^(2/3)) + 1/3*(a^2)^(1/3)*log((b*x^3 + a)^(1/
3)*a - (a^2)^(2/3)) + 1/2*(b*x^3 + a)^(2/3)

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giac [A]  time = 0.69, size = 98, normalized size = 1.00 \[ \frac {1}{3} \, \sqrt {3} a^{\frac {2}{3}} \arctan \left (\frac {\sqrt {3} {\left (2 \, {\left (b x^{3} + a\right )}^{\frac {1}{3}} + a^{\frac {1}{3}}\right )}}{3 \, a^{\frac {1}{3}}}\right ) - \frac {1}{6} \, a^{\frac {2}{3}} \log \left ({\left (b x^{3} + a\right )}^{\frac {2}{3}} + {\left (b x^{3} + a\right )}^{\frac {1}{3}} a^{\frac {1}{3}} + a^{\frac {2}{3}}\right ) + \frac {1}{3} \, a^{\frac {2}{3}} \log \left ({\left | {\left (b x^{3} + a\right )}^{\frac {1}{3}} - a^{\frac {1}{3}} \right |}\right ) + \frac {1}{2} \, {\left (b x^{3} + a\right )}^{\frac {2}{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^3+a)^(2/3)/x,x, algorithm="giac")

[Out]

1/3*sqrt(3)*a^(2/3)*arctan(1/3*sqrt(3)*(2*(b*x^3 + a)^(1/3) + a^(1/3))/a^(1/3)) - 1/6*a^(2/3)*log((b*x^3 + a)^
(2/3) + (b*x^3 + a)^(1/3)*a^(1/3) + a^(2/3)) + 1/3*a^(2/3)*log(abs((b*x^3 + a)^(1/3) - a^(1/3))) + 1/2*(b*x^3
+ a)^(2/3)

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maple [F]  time = 0.12, size = 0, normalized size = 0.00 \[ \int \frac {\left (b \,x^{3}+a \right )^{\frac {2}{3}}}{x}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x^3+a)^(2/3)/x,x)

[Out]

int((b*x^3+a)^(2/3)/x,x)

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maxima [A]  time = 2.95, size = 97, normalized size = 0.99 \[ \frac {1}{3} \, \sqrt {3} a^{\frac {2}{3}} \arctan \left (\frac {\sqrt {3} {\left (2 \, {\left (b x^{3} + a\right )}^{\frac {1}{3}} + a^{\frac {1}{3}}\right )}}{3 \, a^{\frac {1}{3}}}\right ) - \frac {1}{6} \, a^{\frac {2}{3}} \log \left ({\left (b x^{3} + a\right )}^{\frac {2}{3}} + {\left (b x^{3} + a\right )}^{\frac {1}{3}} a^{\frac {1}{3}} + a^{\frac {2}{3}}\right ) + \frac {1}{3} \, a^{\frac {2}{3}} \log \left ({\left (b x^{3} + a\right )}^{\frac {1}{3}} - a^{\frac {1}{3}}\right ) + \frac {1}{2} \, {\left (b x^{3} + a\right )}^{\frac {2}{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^3+a)^(2/3)/x,x, algorithm="maxima")

[Out]

1/3*sqrt(3)*a^(2/3)*arctan(1/3*sqrt(3)*(2*(b*x^3 + a)^(1/3) + a^(1/3))/a^(1/3)) - 1/6*a^(2/3)*log((b*x^3 + a)^
(2/3) + (b*x^3 + a)^(1/3)*a^(1/3) + a^(2/3)) + 1/3*a^(2/3)*log((b*x^3 + a)^(1/3) - a^(1/3)) + 1/2*(b*x^3 + a)^
(2/3)

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mupad [B]  time = 1.08, size = 122, normalized size = 1.24 \[ \frac {{\left (b\,x^3+a\right )}^{2/3}}{2}+\frac {a^{2/3}\,\ln \left (a^2\,{\left (b\,x^3+a\right )}^{1/3}-a^{7/3}\right )}{3}-\frac {a^{2/3}\,\ln \left (a^2\,{\left (b\,x^3+a\right )}^{1/3}-a^{7/3}\,{\left (\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )}^2\right )\,\left (\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )}{3}+a^{2/3}\,\ln \left (a^2\,{\left (b\,x^3+a\right )}^{1/3}-9\,a^{7/3}\,{\left (-\frac {1}{6}+\frac {\sqrt {3}\,1{}\mathrm {i}}{6}\right )}^2\right )\,\left (-\frac {1}{6}+\frac {\sqrt {3}\,1{}\mathrm {i}}{6}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b*x^3)^(2/3)/x,x)

[Out]

(a + b*x^3)^(2/3)/2 + (a^(2/3)*log(a^2*(a + b*x^3)^(1/3) - a^(7/3)))/3 - (a^(2/3)*log(a^2*(a + b*x^3)^(1/3) -
a^(7/3)*((3^(1/2)*1i)/2 + 1/2)^2)*((3^(1/2)*1i)/2 + 1/2))/3 + a^(2/3)*log(a^2*(a + b*x^3)^(1/3) - 9*a^(7/3)*((
3^(1/2)*1i)/6 - 1/6)^2)*((3^(1/2)*1i)/6 - 1/6)

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sympy [C]  time = 2.19, size = 44, normalized size = 0.45 \[ - \frac {b^{\frac {2}{3}} x^{2} \Gamma \left (- \frac {2}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {2}{3}, - \frac {2}{3} \\ \frac {1}{3} \end {matrix}\middle | {\frac {a e^{i \pi }}{b x^{3}}} \right )}}{3 \Gamma \left (\frac {1}{3}\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x**3+a)**(2/3)/x,x)

[Out]

-b**(2/3)*x**2*gamma(-2/3)*hyper((-2/3, -2/3), (1/3,), a*exp_polar(I*pi)/(b*x**3))/(3*gamma(1/3))

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